DMGB / SYSTEMS v426

THE FIELD GUIDE / 005 · ENERGY & HEAT

Following
the heat.

A warm mug, a thick coat, and air rushing past. All show how heat moves or changes form.

Heat travels from warmer things to cooler ones. A layer can slow that journey. When fast air slows, some motion energy can warm the gas. Start with the simple version, then explore the models.

Start with the simple version ↓

A very simple version

Imagine this

Heat moves from hotter things to cooler things. A blanket can slow how fast warmth leaves, but it cannot make heat disappear. Follow heat through every layer and part of the journey.

For curious readers: how it could help and what the evidence says

How it could help people

Today, heat-flow models help compare insulation, cooling time and heating needs in a stated situation. A future cooling design would still need a full-system test.

Evidence and limits

The calculations use things we chose to assume. Real airflow, how parts touch, material properties and changing conditions still need checking.

Read-aloud starter; not yet tested with children. The fuller science, data, figures and sources follow below.

THE SIMPLE VERSION · NO BACKGROUND NEEDED

Heat moves from hotter things to cooler things.

Think of a warm mug in a cool room. Heat leaves the mug and warms the air and your hands. A thick layer around an object can slow that journey, a little like a warm coat slows how quickly your body loses heat.

A coat does not make heat disappear. If the surroundings stay warm long enough, the object inside will warm too. And when warm air slows down, some of its motion energy can become energy inside the gas, so the gas gets hotter.

For a liquid moving through a warm pipe, each small bit of liquid spends less time beside the warm wall when it moves faster. It may warm less on its way through, even though more liquid passes each second.

Two ways heat can travelThe upper path shows warm surroundings passing heat through a layer into an object. The layer slows the transfer but does not stop it forever. The lower path shows fast air slowing, with some motion energy becoming energy inside the gas and raising its temperature.A WARM PLACE HEATS AN OBJECTWARM AIRoutsideLAYERslows heat transferOBJECTwarms over timeFAST AIR SLOWS DOWNFAST AIRSLOWSGAS GETShotter
The paths are separate examples. A gas-temperature calculation is not a prediction of how hot a wall, food or spacecraft part becomes.

Why this can help people

Knowing where heat goes helps engineers design building insulation and temperature control for spacecraft instruments. That can support comfort, lower heating and cooling demand, and protect equipment when the real design is measured and tested. U.S. Department of Energy: home insulation · NASA: spacecraft temperature control

What this page cannot prove

The curves below are simplified calculations, not measurements of a real material or vehicle. They do not show that food is safe, that germs have been killed, or that medicine stays within a safe temperature range. Those questions need their own evidence and tests; see the separate food and hygiene chapter.

Next, follow the rigorous layer: gas slowing, heat crossing layers, liquid flow and their assumptions, graphs and downloadable methods. The simple explanation and the scientific account use the same evidence.

01 / MOTION BECOMES INTERNAL ENERGY

What happens when air slows down?

Imagine bringing a stream of air to rest without exchanging heat with its surroundings. The final gas temperature is called its stagnation temperature. Mach number measures speed relative to the local speed of sound.

Temperatures use kelvin (K), an absolute scale. Subtract 273.15 to convert K to °C.

Fixed heat capacity
With molecular vibration
Model difference

Two simplified stagnation-temperature models from Mach 0 to 5.

Dashed pink: fixed heat capacity. Solid blue: molecular vibration included. The dot marks your selected speed. At high temperatures both models omit chemical changes in the gas.

This is gas temperature, not wall temperature or heat flux. A real surface also involves flow geometry, heat transfer, radiation and the material response.

02 / WHY THE CURVES SEPARATE

Energy has more
places to go.

At lower temperatures, a simple model assigns nearly constant heat capacity to air. At higher temperatures, more energy can enter molecular vibration. The same energy input then produces a smaller temperature rise.

01

Start with the incoming state

Mach number alone is insufficient. Change the incoming temperature and the final temperature changes too.

02

Keep the model in view

The blue curve includes one additional physical effect. It is not a complete real-air calculation: dissociation, ionization and chemical nonequilibrium are absent.

03 / FOLLOW THE TRANSFER

How long does a layer buy you?

An inert, well-mixed payload starts at 20 °C. Its surroundings stay at 80 °C. Heat crosses an external convection boundary and two ideal layers. Increase the first layer’s thickness and see how slowly the payload warms.

Higher conductivity lets heat through more easily. These are illustrative values, not certified material specifications.

Payload temperature
Current heat-transfer rate
Energy received

The thermal-resistance pathAn 80 degree environment passes heat through convection, layer one, then layer two, into a uniform payload. The text above reports the interface temperature.80 °CConvectionLayer 1adjustableLayer 22 mmPayload
The payload approaches its 80 degree surroundings over time.

Insulation delays change; it does not create cold. Given enough time, this payload approaches 80 °C for every finite resistance.

What is being assumed?

Area A = 0.1 m²; payload heat capacity C = 2,000 J/K; external convection h = 10 W/(m² K); second layer thickness = 2 mm and conductivity = 0.2 W/(m K). Both layers have negligible heat storage and perfect contact. Heat travels in one dimension.

Resistance R = 1/(hA) + L₁/(k₁A) + L₂/(k₂A), in K/W. The energy balance C dT/dt = (Tᵦ − T)/R gives T(t) = Tᵦ + (T₀ − Tᵦ) exp[−t/(RC)]. Heat rate is (Tᵦ − T)/R; energy gained is C(T − T₀). The layer-interface temperature follows the same instantaneous heat rate through both layers.

This quasi-steady layer model cannot show a heat front propagating through a massive shield, melting, ablation, radiation, stress or structural failure.

04 / LIQUID IN MOTION

Less time, less temperature change.

A liquid enters a heated passage at 20 °C. The wall stays at 80 °C. Speed up the flow: each kilogram receives less energy during its passage.

For fixed overall conductance UA = 10 W/K and specific heat cₚ = 4,200 J/(kg K), the steady plug-flow energy balance gives Tₒᵤₜ = Tᵦ + (Tᵢₙ − Tᵦ) exp[−UA/(ṁcₚ)]. This separate passage model assumes constant properties, no phase change and negligible axial conduction.

The liquid warms along the passage. Values are also available in the table and CSV below.

UA describes the whole passage; it is not taken from the flat layers above. It is deliberately held fixed as flow changes; a real passage’s conductance may also change with flow. Pressure drop, flow mixing, heater control, cleaning and food safety require separate analysis.

05 / LOOK INSIDE

A cold surface.
A warmer centre.

Now consider a different object: a solid sheet 20 mm thick, initially at 20 °C. At time zero, both faces are held at 5 °C. Heat inside must diffuse toward the faces. Move time forward to see the interior catch up.

The illustrative thermal diffusivity is 10⁻⁷ m²/s. Larger diffusivity means a temperature disturbance spreads faster.

Both faces5.0 °C
Centre temperature
Centre minus face

The two faces are cooler than the centre during the transient.

A surface sensor alone can miss heat still stored inside. In this model, doubling the sheet thickness makes the same temperature profile take four times as long: the diffusion timescale is proportional to thickness squared.

How this differs from the earlier payload model

This calculation resolves temperature across an inert solid. It assumes a wide plane sheet, constant properties and perfectly controlled face temperatures. It does not use the earlier convection-and-layer boundary conditions, so these are separate examples, not competing predictions of the same object.

The heat equation is ∂T/∂t = α ∂²T/∂x². Here the half-thickness L is 0.01 m, and the Fourier number Fo = αt/L² measures elapsed time relative to diffusion. A 64-term cosine series solves the stated fixed-face problem; the downloadable code gives its coefficients.

The face temperature changes instantaneously in this idealization. The earliest displayed time is one second; we do not calculate the instantaneous boundary jump. There is no freezing, internal heating, edge loss, fluid movement or temperature-dependent material behavior.

A uniform-temperature approximation is useful only when internal gradients are small. For convection at an object’s surface, the Biot number Bi = hL꜀/k helps assess that condition; L꜀ is volume / surface area, and k is the object’s conductivity. Bi around 0.1 is a common heuristic, not a universal switch. The fixed-face example here deliberately permits substantial gradients.

These are inert-material calculations. They do not establish biological preservation, food safety or human heat-exposure limits.

INSPECT YOUR SETTINGS

The numbers behind
the moving curves.

These tables follow your current controls. Downloads include the more finely sampled curves, units and selected inputs.

Air: selected curve points
Gas temperatures at the selected incoming temperature
MachFixed capacity (K)Vibrational (K)
Payload: selected time points
Current layer settings over three hours
Time (min)Payload (°C)Heat rate (W)Energy gained (kJ)
Liquid: along the passage
Current liquid flow through the heated passage
Passage fractionTemperature (°C)Heat received so far (W)
Sheet: from face to centre to face
Current time, measured across the 20 mm sheet
Position from left face (mm)Temperature (°C)

A HISTORICAL OBSERVATION · LIMITED EVIDENCE

Observing an event is not testing its explanation.

A 1935 Nature account describes one firewalking demonstration. The observer recorded a sole-surface temperature of about 93.2 °F (34.0 °C) around 20 minutes before the walk and about 93.0 °F (33.9 °C) roughly 10 seconds afterward. The account says the feet had been washed and dried about 15 minutes earlier. These are observations from one reported event, not a controlled test of why it happened.

What the report measured—and what it did not establish
ObservationWhat it can supportWhat it cannot establish
Two sole-surface readings, before and shortly after one eventA limited record of that reported demonstrationThe cause, heat flux during contact, or a sweat-and-evaporation effect
No controlled dry-versus-wet comparison or detailed ember measurementsA reason to keep the explanation openA general safety claim or a repeatable protection method

The models on this page use specified, inert boundaries. They do not model skin or reproduce firewalking, and this site does not recommend trying it. Read the 1935 Nature report.

06 / REPRODUCIBLE CALCULATIONS

Read the curves
like a study.

DETERMINISTIC TEACHING MODELS · NO EXPERIMENTAL MEASUREMENTS

Calculated stagnation temperatures and model differences versus Mach number for incoming air at 220 and 300 kelvin.
Figure 1. Slowing air. Two simplified gas models over 202 settings. Their difference illustrates model sensitivity, not an empirical error bar. Chemical reactions are excluded.
Payload temperature and accumulated energy versus time for three illustrative layer conductivities.
Figure 2. Delaying heat transfer. Three calculated warming histories, 543 time samples. Fixed ambient temperature, negligible layer heat storage and a uniform payload are assumed. These are not measurements of a protective product.
Thermal resistance and response time as layer thickness increases, for three conductivities.
Figure 3. Thickness and conductivity. 150 prescribed layer combinations. Compare resistance and response time while holding area, convection and payload heat capacity fixed.
For three flow rates, temperature rises along a heated passage. Total heat transfer rises with flow even as the outlet temperature falls.
Figure 4. Temperature rise and total energy transfer differ. The same conductance heats more mass each second at larger flow. Each kilogram warms less, but the total transfer rate can increase. All curves hold UA fixed; 5,050 calculated values sample 50 flows and 101 passage positions.
Four profiles show the centre cooling later than the sheet faces. Time histories distinguish centre temperature, average temperature and the imposed face temperature.
Figure 5. Resolving the interior. Four temperature profiles (804 samples) and 241 time-history points for the 20 mm sheet. Centre, average and surface temperatures are different quantities. The time-history axis is logarithmic.

Run each downloaded Python script in its own folder with Matplotlib installed; the spatial study also requires NumPy. The scripts write beside themselves. File headers identify units and prescribed inputs.

Reference values and model checks

An independent finite-difference solution approaches the sheet’s series solution as its grid is refined: maximum differences at four tested times fall from 0.03037 to 0.007668 to 0.001921 °C with 100, 200 and 400 intervals. This checks the specified calculation, not a real material. For the liquid, a separate numerical integration over 100 segments differs from the analytical outlet formula by less than 0.000001 °C across the exported flow range.

At Mach 0, both gas models return the incoming temperature. With air at 220 K and Mach 2, the fixed-capacity result is 396 K. Initially, the payload is 20 °C with zero energy gained. After one time constant RC, it has covered 63.2% of the temperature difference, reaching 57.9 °C.

The fixed-capacity gas relation is Tₜ = T[1 + (γ − 1)M²/2], with γ = 1.4. The vibrational relation and characteristic temperature 5,500 °R (3,055.56 K) follow NASA’s model below; the implicit equation is solved by bisection.

FROM A MODEL TO A TEST

A design question
you can actually check.

Suppose an inert instrument package must stay below 40 °C for one hour in the model’s 80 °C surroundings. It starts at 20 °C and has the same 2,000 J/K heat capacity. Solving the temperature equation requires total resistance of at least 4.44 K/W.

With the other settings unchanged and first-layer conductivity 0.04 W/(m K), the ideal calculation needs about 13.4 mm of that layer. At 14 mm, the predicted temperature after one hour is 39.4 °C. If conductivity is 20% higher than assumed, the same 14 mm layer predicts 41.7 °C after one hour and misses the requirement. This sensitivity is illustrative, not a measured uncertainty distribution. This is a calculation for a hypothetical requirement, not a material recommendation or a certified enclosure.

Proposed measurement protocol — not an experiment already performed
  1. Define an inert test object with documented mass, heat capacity, layer dimensions, area and contact arrangement. Record which surfaces can exchange heat.
  2. Check the temperature sensors together at stable reference temperatures across the intended range. Record their specified uncertainty, resolution, response time and any observed offsets.
  3. Measure the environment, outer surface, layer interface and at least two positions inside the payload on a common timebase. Internal disagreement tests the uniform-temperature assumption.
  4. Repeat controlled heating or cooling runs with at least two layer thicknesses. Keep the boundary conditions and initial temperatures comparable. The real environment may not reproduce an ideal fixed temperature or convection coefficient.
  5. Compare entire recorded temperature histories with predictions using independently measured inputs. Inspect residuals, repeatability and energy balance. Do not merely adjust an unknown resistance until a curve looks similar.
  6. Report the difference at the chosen one-hour endpoint and its uncertainty. A run only supports the stated temperature requirement if its uncertainty range and boundary conditions justify that conclusion.

These are proposed measurements, not results supplied by this page. Sensor lag, uncertain conductivity, imperfect contact and edge losses can all shift the curve. A close numerical solution cannot remove those physical uncertainties.

07 / WHAT THIS COULD IMPROVE

Design around the whole journey.

INSULATION

Buy useful time

Estimate how resistance and heat capacity change temperature drift before selecting materials for controlled measurements.

LIQUID HANDLING

Match flow and heating

Understand why a faster flow can leave a passage cooler even when its wall temperature stays the same.

THERMAL PROTECTION

Separate the questions

First estimate the flow state, then heat transfer, then the object’s response. No single gas-temperature number answers all three.

READ FURTHER

The physical foundations.

NASA Glenn · Stagnation temperature and real-gas effects supplies the gas relations.

MIT · Thermal resistance circuits derives transfer through layers.

MIT · Dimensionless analysis explains the uniform-temperature approximation.

MIT · Heat exchangers, uniform wall temperature derives the exponential liquid-temperature relation.

MIT OpenCourseWare · Transient heat conduction gives the fixed-face plate solution used for the sheet.

Revised 27 September 2026. Original educational calculations, not a peer-reviewed material or flight evaluation.

A target temperature is not a cooling system.

One proposed membrane is assigned a temperature of 0.000825 kelvin—0.825 millikelvin above absolute zero. The description provides no cooling power, heat-leak budget, material behavior or temperature measurement supporting that condition. The ordinary-temperature examples here cannot be extrapolated to demonstrate it.